My Circuit

A low-cost circuit of an FM booster that can be used to listen programs from distant FM stations clearly. The circuit comprises a common-emitter tuned RF preamplifier wired around VHF/UHF transistor 2SC2570 ( C2570). this FM booster circuit is constructed using few common components( not require some special components ) and provide a very good gain .to calibrate this circuit you need to adjust input/output trimmers (VC1/VC2) for maximum gain. FM Booster Circuit Diagram Circuit Diagram  Input coil L1 consists of four turns of 20SWG enamelled copper wire (slightly space wound) over 5mm diameter former. It is tapped at the first turn from ground lead side. Coil L2 is similar to L1, but has only three turns. Both of the trimmers are 22pF value. This FM radio signal booster needs to be powered by a 12 volts DC power supply .

The HP series Hydrophone Booster Amplifier (HA2) amplifies low-level hydrophone signals over a wide range of frequencies. It has a minimum gain of 25dB and an input and output impedance of 50Ω. The HA2 is designed for use with either Precision Acoustics membrane hydrophone or Precision Acoustics HP Series Hydrophone Measurement System, which is shown in Fig 1. Alternatively, the HA2 may be used when the acoustic signal is provided by a high output impedance hydrophone, such as a GEC-Marconi membrane device, or a conventional hydrophone. In this instance a BNC/MCX adaptor is used which connects directly to the HP Series Submersible Preamplifier, using it as a buffer amplifier, (i.e. the standard Precision Acoustic HP Series configuration shown in Fig 1 is used, but without the interchangeable probe). . The HA2 amplifier is straightforward to use but the following points should be noted: The output of the amplifier should be correctly terminated in 50Ω before operation. The HA2 amplifi...

The above circuit is a circuit of booster amplifiers or amplifier end of a power amplifier circuit, Circuit over in the most important influence whether or not , and many more are affected in this final series.  Because the booster circuit is the amplifier end of the work was too heavy components causing the rapid component of the heat. If we are wrong then consequences will install components that can cause fatal damaged direct component , such us the installation of pin emiter, collector , and base everything must be correct. In the circuit above can strengthen booster amplifier with maximum work and everything is evenly split, what is it evenly split ? evenly split the point here is that all components can work with the same voltage and the heat evenly , this is because at each respetive base transistor were given the same constrains and same wattage resistor. And to maintain if the power output is too large then the resistor on Re will hamper so that the transistor is not easil...